4=e^{3k}

Lösung

4 = e^{3 k}

k = \frac{2 ln ( 2 )}{3}

Dezimale

k = 0.46209 \dots

Schritte zur Lösung

4 = e^{3 k}

Wende Exponentenregel an

ln (4) = 3 k

Löse

ln (4) = 3 k : k = \frac{2 ln ( 2 )}{3}

k = \frac{2 ln ( 2 )}{3}

A (B^{\frac{1}{x}} + C) = D

1 6^{2 x + 1} = 4^{1 - x}

t = 0.05 e^{0.086664 \cdot t}

2 \cdot 2^{2 x} = 17 \cdot 2^{x} - 8

(32)^{2 - x} = 2^{x^{2}}