2(3)^{2x+1}=5^{x-3}

Lösung

2 (3)^{2 x + 1} = 5^{x - 3}

x = - \frac{ln ( 750 )}{2 ln ( 3 ) - ln ( 5 )}

Dezimale

x = - 11.26271 \dots

Schritte zur Lösung

2 (3)^{2 x + 1} = 5^{x - 3}

Wende Exponentenregel an

ln (2) + (2 x + 1) ln (3) = (x - 3) ln (5)

Löse

ln (2) + (2 x + 1) ln (3) = (x - 3) ln (5) : x = - \frac{ln ( 750 )}{2 ln ( 3 ) - ln ( 5 )}

x = - \frac{ln ( 750 )}{2 ln ( 3 ) - ln ( 5 )}

4^{\frac{2 x}{3}} = 8^{x + 2}

67 \cdot 3^{2 x} = 536

9^{x} = (\frac{1}{9})^{x + 3}

(\frac{6}{5})^{n} = 16

4^{2 x - 3} = 1