2^x=0.5e^{-1x}

Lösung

2^{x} = 0.5 e^{- 1 x}

x = \frac{ln ( 0.5 )}{ln ( 2 ) + 1}

Dezimale

x = - 0.40938 \dots

Schritte zur Lösung

2^{x} = 0.5 e^{- 1 \cdot x}

Wende Exponentenregel an

x ln (2) = ln (0.5) - 1 \cdot x

Löse

x ln (2) = ln (0.5) - 1 \cdot x : x = \frac{ln ( 0.5 )}{ln ( 2 ) + 1}

x = \frac{ln ( 0.5 )}{ln ( 2 ) + 1}

4 = e^{9 (6) + c_{1}}

x \cdot e^{- x} = 0

2 7^{9^{7 - x}} = 33

3 2^{n} = 8

1.0 5^{x} = 50000