e^{ln(5x)}=2

Lösung

e^{l n (5 x)} = 2

x = \frac{2}{5}

Dezimale

x = 0.4

Schritte zur Lösung

e^{l n (5 x)} = 2

Wende Exponentenregel an

ln (5 x) = ln (2)

Löse

ln (5 x) = ln (2) : x = \frac{2}{5}

x = \frac{2}{5}

e^{x} = 10000

so l v e f or n, x = 7^{n}

4^{2 x - 1} = 9^{- 4 x + 5}

e^{3 x - 1} = 1

- 8 \cdot 9^{- 5 x} = - 49