4^{x+1}=8^{2x+3}

Lösung

4^{x + 1} = 8^{2 x + 3}

x = - \frac{7}{4}

Dezimale

x = - 1.75

Schritte zur Lösung

4^{x + 1} = 8^{2 x + 3}

Wende Exponentenregel an

2 (x + 1) = 3 (2 x + 3)

Löse

2 (x + 1) = 3 (2 x + 3) : x = - \frac{7}{4}

x = - \frac{7}{4}

(1000) 1.0 5^{3 x} = 3000

4 9^{x} = 21

320000 = 250342 e^{0.012 x}

3^{5 x + 34} = 81

0 = \frac{4 e ^{x}}{( 4 + e ^{x} ) ^{2}}