5*25^{x+1}=125^{2x}

Lösung

5 \cdot 2 5^{x + 1} = 12 5^{2 x}

x = \frac{3}{4}

Dezimale

x = 0.75

Schritte zur Lösung

5 \cdot 2 5^{x + 1} = 12 5^{2 x}

Wende Exponentenregel an

2 (x + 1) + 1 = 6 x

Löse

2 (x + 1) + 1 = 6 x : x = \frac{3}{4}

x = \frac{3}{4}

2^{- x - 7} = 1 1^{2 x}

1 6^{x + 4} = 6 4^{4 x - 2}

5^{3 x + 2} = 25

2^{x - 1} = 2^{2 x + 8}

5^{2 x + 1} - 26 \cdot 5^{x} + 5 = 0