4^x3^{x+1}=12^{2x-1}

Lösung

4^{x} 3^{x + 1} = 1 2^{2 x - 1}

x = \frac{2 ln ( 6 )}{ln ( 12 )}

Dezimale

x = 1.44211 \dots

Schritte zur Lösung

4^{x} \cdot 3^{x + 1} = 1 2^{2 x - 1}

Wende Exponentenregel an

x ln (12) + ln (3^{1}) = (2 x - 1) ln (12)

Löse

x ln (12) + ln (3^{1}) = (2 x - 1) ln (12) : x = \frac{2 ln ( 6 )}{ln ( 12 )}

x = \frac{2 ln ( 6 )}{ln ( 12 )}

6640 = 5000 (1 + 0.001)^{T}

e^{x} = 2 x + 1

e^{x} = 2 x + 2

2^{3 x - 4} = 18

3 \cdot (2)^{x - 1} - 2 = 0