(1/9)^{x-5}=27

Lösung

(\frac{1}{9})^{x - 5} = 27

x = \frac{7}{2}

Dezimale

x = 3.5

Schritte zur Lösung

(\frac{1}{9})^{x - 5} = 27

Wende Exponentenregel an

- 2 (x - 5) = 3

Löse

- 2 (x - 5) = 3 : x = \frac{7}{2}

x = \frac{7}{2}

5 = 1 5^{2 - 0.01 q}

e^{x} - 6 e^{x} - 1 = 0

0 = 3 e^{3 x} (10 - 6 x) + e^{3 x} (- 6)

\frac{1}{5} = e^{- 3 t}

2 (3^{2 x}) + 7 (3^{x}) - 15 = 0