30000=700*2^{2t}

解答

30000 = 700 \cdot 2^{2 t}

t = \frac{ln ( \frac{300}{7} )}{2 ln ( 2 )}

十进制

t = 2.71073 \dots

求解步骤

30000 = 700 \cdot 2^{2 t}

交换两边

700 \cdot 2^{2 t} = 30000

两边除以

700

2^{2 t} = \frac{300}{7}

使用指数运算法则

2 t ln (2) = ln (\frac{300}{7})

解

2 t ln (2) = ln (\frac{300}{7}) : t = \frac{ln ( \frac{300}{7} )}{2 ln ( 2 )}

t = \frac{ln ( \frac{300}{7} )}{2 ln ( 2 )}

375 = 1500 \cdot 0.99 3^{t}

3^{2 x + 8} = 9^{3 x - 10}

5 \cdot 2^{3 x + 1} = 30

e^{- x^{2}} (1 - 2 x^{2}) = 0

so l v e f or n, (x^{4})^{n} = x^{16}