2^n=40

Lösung

2^{n} = 40

n = \frac{ln ( 40 )}{ln ( 2 )}

Dezimale

n = 5.32192 \dots

Schritte zur Lösung

2^{n} = 40

Wende Exponentenregel an

n ln (2) = ln (40)

Löse

n ln (2) = ln (40) : n = \frac{ln ( 40 )}{ln ( 2 )}

n = \frac{ln ( 40 )}{ln ( 2 )}

3^{2 x + 5} = 81

20 (1.07)^{x} = 8 (1.13)^{x}

7.9 (1.3)^{1.3 x} = 352

(1 + 0.06)^{x} = 4800000

a^{x} = 3