6^{2x+1}=5^x

解

6^{2 x + 1} = 5^{x}

x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

十進法表記

x = - 0.90764 \dots

解答ステップ

6^{2 x + 1} = 5^{x}

指数の規則を適用する

(2 x + 1) ln (6) = x ln (5)

解く

(2 x + 1) ln (6) = x ln (5) : x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}