6^{2x+1}=5^x

Lösung

6^{2 x + 1} = 5^{x}

x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

Dezimale

x = - 0.90764 \dots

Schritte zur Lösung

6^{2 x + 1} = 5^{x}

Wende Exponentenregel an

(2 x + 1) ln (6) = x ln (5)

Löse

(2 x + 1) ln (6) = x ln (5) : x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

x = - \frac{ln ( 6 )}{2 ln ( 6 ) - ln ( 5 )}

\frac{1}{81} 3^{5 x + 1} = 81

8 (2)^{x} = 2^{x + 3}

5^{x + 5} = 750

7^{y - 3} = 50

9^{x + 2} = 8 1^{5 x - 4}