3^x=4^{x+1}

Lösung

3^{x} = 4^{x + 1}

x = \frac{2 ln ( 2 )}{ln ( 3 ) - 2 ln ( 2 )}

Dezimale

x = - 4.81884 \dots

Schritte zur Lösung

3^{x} = 4^{x + 1}

Wende Exponentenregel an

x ln (3) = (x + 1) ln (4)

Löse

x ln (3) = (x + 1) ln (4) : x = \frac{2 ln ( 2 )}{ln ( 3 ) - 2 ln ( 2 )}

x = \frac{2 ln ( 2 )}{ln ( 3 ) - 2 ln ( 2 )}

e^{x} = x + 2

e^{x} = - 7

2^{2 x - 1} = \frac{1}{8}

e^{7 x + 7} = 7 e^{7 - x}

(\frac{2}{3})^{x} = 2^{x - 1}