16^{-7x}=72

Lösung

1 6^{- 7 x} = 72

x = - \frac{ln ( 72 )}{28 ln ( 2 )}

Dezimale

x = - 0.22035 \dots

Schritte zur Lösung

1 6^{- 7 x} = 72

Wende Exponentenregel an

- 7 x ln (16) = ln (72)

Löse

- 7 x ln (16) = ln (72) : x = - \frac{ln ( 72 )}{28 ln ( 2 )}

x = - \frac{ln ( 72 )}{28 ln ( 2 )}

5^{2 x - 1} = 6

5^{2 x + 4} = \frac{1}{625}

e^{a} = 35

4150 = 2300 (1.06)^{x}

10 = (0.01)^{x}