9^{x-1}=7

Lösung

9^{x - 1} = 7

x = \frac{ln ( 7 )}{2 ln ( 3 )} + 1

Dezimale

x = 1.88562 \dots

Schritte zur Lösung

9^{x - 1} = 7

Wende Exponentenregel an

(x - 1) ln (9) = ln (7)

Löse

(x - 1) ln (9) = ln (7) : x = \frac{ln ( 7 )}{2 ln ( 3 )} + 1

x = \frac{ln ( 7 )}{2 ln ( 3 )} + 1

3 e^{x} + 1 = 5

e^{2 x} + e^{3 x} = 0

1 0^{\frac{z}{3}} = 7

64 = 3 2^{- x + 1}

e^{x^{2} - 21} = e^{4}