8^{2x+3}=2^x

Lösung

8^{2 x + 3} = 2^{x}

x = - \frac{9}{5}

Dezimale

x = - 1.8

Schritte zur Lösung

8^{2 x + 3} = 2^{x}

Wende Exponentenregel an

3 (2 x + 3) = x

Löse

3 (2 x + 3) = x : x = - \frac{9}{5}

x = - \frac{9}{5}

- 4 + 4 e^{(8 x + 2.5)} = 84

e^{x^{2}} = 3

3^{x} = 9^{2 x - 1}

3^{7 x} = 3.3

\frac{1}{3} \cdot 2^{x} = 12