What is the answer to 2^{2x-1}-6*2^{x-1}=0 ?

The answer to 2^{2x-1}-6*2^{x-1}=0 is x=(ln(6))/(ln(2))

Solve for x: 2^{2x-1}-6*2^{x-1}=0

The solution is x=(ln(6))/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2 x - 1} - 6 \cdot 2^{x - 1} = 0

x = \frac{ln ( 6 )}{ln ( 2 )}

Decimal Notation

x = 2.58496 \dots

Solution steps

2^{2 x - 1} - 6 \cdot 2^{x - 1} = 0

Add

6 \cdot 2^{x - 1}

to both sides

2^{2 x - 1} - 6 \cdot 2^{x - 1} + 6 \cdot 2^{x - 1} = 0 + 6 \cdot 2^{x - 1}

Simplify

2^{2 x - 1} = 6 \cdot 2^{x - 1}

Apply exponent rules

(2 x - 1) ln (2) = ln (6) + (x - 1) ln (2)

Solve

(2 x - 1) ln (2) = ln (6) + (x - 1) ln (2) : x = \frac{ln ( 6 )}{ln ( 2 )}

x = \frac{ln ( 6 )}{ln ( 2 )}

x, 2^{- x} = 0

(0.5)^{2 x - 5} = 256

25 e^{\frac{x}{2}} = 750

N, F = P \cdot (1 + x)^{N}

What is the answer to 2^{2x-1}-6*2^{x-1}=0 ?
The answer to 2^{2x-1}-6*2^{x-1}=0 is x=(ln(6))/(ln(2))
Solve for x: 2^{2x-1}-6*2^{x-1}=0
The solution is x=(ln(6))/(ln(2))