(x-3)^{5x+1}=(x-3)^{x^2-5}

Lösung

(x - 3)^{5 x + 1} = (x - 3)^{x^{2} - 5}

x = 4, x = 6

Schritte zur Lösung

(x - 3)^{5 x + 1} = (x - 3)^{x^{2} - 5}

Wende Exponentenregel an

(5 x + 1) ln (x - 3) = (x^{2} - 5) ln (x - 3)

Löse

(5 x + 1) ln (x - 3) = (x^{2} - 5) ln (x - 3) : x = 4, x = 6

x = 4, x = 6

2 = 1.042 5^{x}

3 3^{x - 2} = 1 7^{8 x}

57 = 2 7^{x}

2 = (0.0225)^{x}

so l v e f or x, 4^{x} - 2 (8^{y}) = 0