3^{4x}=7^{x^2}

Lösung

3^{4 x} = 7^{x^{2}}

x = 0, x = \frac{4 ln ( 3 )}{ln ( 7 )}

Dezimale

x = 0, x = 2.25830 \dots

Schritte zur Lösung

3^{4 x} = 7^{x^{2}}

Wende Exponentenregel an

4 x ln (3) = x^{2} ln (7)

Löse

4 x ln (3) = x^{2} ln (7) : x = 0, x = \frac{4 ln ( 3 )}{ln ( 7 )}

x = 0, x = \frac{4 ln ( 3 )}{ln ( 7 )}

5^{x^{2}} = 2 5^{3 x - 4}

8^{x - 2} = 125

3 2 5^{2} = 5^{p}

3^{2 n - 1} = \frac{1}{81}

3^{x + 1} + 3^{x + 2} + 3^{x - 1} = 999