7^{-3x}=11^{x+8}

Lösung

7^{- 3 x} = 1 1^{x + 8}

x = - \frac{8 ln ( 11 )}{ln ( 3773 )}

Dezimale

x = - 2.32929 \dots

Schritte zur Lösung

7^{- 3 x} = 1 1^{x + 8}

Wende Exponentenregel an

- 3 x ln (7) = (x + 8) ln (11)

Löse

- 3 x ln (7) = (x + 8) ln (11) : x = - \frac{8 ln ( 11 )}{ln ( 3773 )}

x = - \frac{8 ln ( 11 )}{ln ( 3773 )}

3^{x} = - 2 in

7^{- x} = 2

2^{3 y} - 2^{2 y} - 2^{y + 1} = 0

so l v e f or x, ln (y) = e^{x} + ln (2)

so l v e f or u, y = x^{u}