2^{(x+1)}=3

Lösung

2^{(x + 1)} = 3

x = \frac{ln ( 3 )}{ln ( 2 )} - 1

Dezimale

x = 0.58496 \dots

Schritte zur Lösung

2^{(x + 1)} = 3

Wende Exponentenregel an

(x + 1) ln (2) = ln (3)

Löse

(x + 1) ln (2) = ln (3) : x = \frac{ln ( 3 )}{ln ( 2 )} - 1

x = \frac{ln ( 3 )}{ln ( 2 )} - 1

7^{x} = \frac{1}{3 7}

2 z^{(2 - 7 z)} = 0

2 5^{x} = 35

73 = 2 7^{x}

4^{x + 7} = 5