solvefor n,(1+i)^n=i

Lösung

löse nach

n, (1 + i)^{n} = i

n = \frac{ln ( i )}{ln ( 1 + i )}

Schritte zur Lösung

(1 + i)^{n} = i

Wende Exponentenregel an

n ln (1 + i) = ln (i)

Löse

n ln (1 + i) = ln (i) : n = \frac{ln ( i )}{ln ( 1 + i )}

n = \frac{ln ( i )}{ln ( 1 + i )}

77 = 1 7^{x}

40 = 20 (1 0^{0.1 x})

2^{3 x + 5} = 2^{1 - x}

e^{\frac{k}{6}} = a

1 0^{x} = 3588