5^x=3^{2x+1}

Lösung

5^{x} = 3^{2 x + 1}

x = \frac{ln ( 3 )}{ln ( 5 ) - 2 ln ( 3 )}

Dezimale

x = - 1.86906 \dots

Schritte zur Lösung

5^{x} = 3^{2 x + 1}

Wende Exponentenregel an

x ln (5) = (2 x + 1) ln (3)

Löse

x ln (5) = (2 x + 1) ln (3) : x = \frac{ln ( 3 )}{ln ( 5 ) - 2 ln ( 3 )}

x = \frac{ln ( 3 )}{ln ( 5 ) - 2 ln ( 3 )}

7^{2 x + 5} = 5 \cdot (3^{3 x})

2^{x} = \frac{4 ^{x - 2}}{8}

6 e^{1 - x} + 1 = 25

1500000 = 3 (2^{x - 1})

e^{- 4 x} = (e^{8})^{1 - x}