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Beliebt Algebra >

6x^4-25x^3+12x^2+25x+6=0

Lösung

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

Lösung

x = 2, x = 3, x = - \frac{1}{3}, x = - \frac{1}{2}

+1

Dezimale

x = 2, x = 3, x = - 0.33333 \dots, x = - 0.5

Schritte zur Lösung

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 = 0

Faktorisiere

6 x^{4} - 25 x^{3} + 12 x^{2} + 25 x + 6 : (x - 2) (x - 3) (3 x + 1) (2 x + 1)

(x - 2) (x - 3) (3 x + 1) (2 x + 1) = 0

Anwendung des Nullfaktorprinzips: Wenn

ab = 0

dann

a = 0

oder

b = 0

x - 2 = 0 or x - 3 = 0 or 3 x + 1 = 0 or 2 x + 1 = 0

Löse

x - 2 = 0 : x = 2

Löse

x - 3 = 0 : x = 3

Löse

3 x + 1 = 0 : x = - \frac{1}{3}

Löse

2 x + 1 = 0 : x = - \frac{1}{2}

Die Lösungen sind

x = 2, x = 3, x = - \frac{1}{3}, x = - \frac{1}{2}

Graph

Beliebte Beispiele

- x^{3} + 3 x^{2} = 0

x^{7} - 1 = 0

(y - 2)^{4} = 0

-x^3+x^2+4x+6=0

- x^{3} + x^{2} + 4 x + 6 = 0

solvefor r,x= 4/3 pir^3

so l v e f or r, x = \frac{4}{3} π r^{3}