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受欢迎的代数 >

solvefor F,t=(F^3+G)a

解答

求解

F, t = (F^{3} + G) a

解答

F = 3 \frac{t}{a} - G, F = - \frac{3 \frac{t}{a} - G}{2} + \frac{3 \frac{t}{a} - G 3}{2} i, F = - \frac{3 \frac{t}{a} - G}{2} - \frac{3 \frac{t}{a} - G 3}{2} i; a \neq = 0

求解步骤

t = (F^{3} + G) a

交换两边

(F^{3} + G) a = t

两边除以

a; a \neq = 0

F^{3} + G = \frac{t}{a}; a \neq = 0

将

G

到右边

F^{3} = \frac{t}{a} - G; a \neq = 0

对于

x^{3} = f (a)

解为

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

F = 3 \frac{t}{a} - G, F = 3 \frac{t}{a} - G \frac{- 1 + 3 i}{2}, F = 3 \frac{t}{a} - G \frac{- 1 - 3 i}{2}; a \neq = 0

化简

3 \frac{t}{a} - G \frac{- 1 + 3 i}{2} : - \frac{3 \frac{t}{a} - G}{2} + \frac{3 \frac{t}{a} - G 3}{2} i

化简

3 \frac{t}{a} - G \frac{- 1 - 3 i}{2} : - \frac{3 \frac{t}{a} - G}{2} - \frac{3 \frac{t}{a} - G 3}{2} i

F = 3 \frac{t}{a} - G, F = - \frac{3 \frac{t}{a} - G}{2} + \frac{3 \frac{t}{a} - G 3}{2} i, F = - \frac{3 \frac{t}{a} - G}{2} - \frac{3 \frac{t}{a} - G 3}{2} i; a \neq = 0

作图

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