z^3=2^{5/2}(1+i)

解

z^{3} = 2^{\frac{5}{2}} (1 + i)

z = \frac{1 + 3 ^{\frac{1}{2}}}{2 ^{\frac{1}{2}}} + i \frac{- 1 + 3}{2 ^{\frac{1}{2}}}, z = - 2^{\frac{1}{2}} + 2^{\frac{1}{2}} i, z = \frac{1 - 3 ^{\frac{1}{2}}}{2 ^{\frac{1}{2}}} + i \frac{- 1 - 3}{2 ^{\frac{1}{2}}}

解答ステップ

z^{3} = 2^{\frac{5}{2}} (1 + i)

簡素化

2^{\frac{5}{2}} (1 + i) : 4 \cdot 2^{\frac{1}{2}} + 4 \cdot 2^{\frac{1}{2}} i

z^{n} = a

の場合, 解は

z_{k} = n ∣ a ∣ (cos (\frac{ar g ( a ) + 2 kπ}{n}) + i sin (\frac{ar g ( a ) + 2 kπ}{n})),

k = 0, 1, \dots, n - 1

以下のため:

n = 3, a = 4 \cdot 2^{\frac{1}{2}} + 4 \cdot 2^{\frac{1}{2}} i

∣ a ∣ = 8

ar g (a) = \frac{π}{4}

z = 38 (cos (\frac{\frac{π}{4} + 2 \cdot 0 π}{3}) + i sin (\frac{\frac{π}{4} + 2 \cdot 0 π}{3})), z = 38 (cos (\frac{\frac{π}{4} + 2 \cdot 1 π}{3}) + i sin (\frac{\frac{π}{4} + 2 \cdot 1 π}{3})), z = 38 (cos (\frac{\frac{π}{4} + 2 \cdot 2 π}{3}) + i sin (\frac{\frac{π}{4} + 2 \cdot 2 π}{3}))

簡素化

38 (cos (\frac{\frac{π}{4} + 2 \cdot 0 π}{3}) + i sin (\frac{\frac{π}{4} + 2 \cdot 0 π}{3})) : \frac{1 + 3 ^{\frac{1}{2}}}{2 ^{\frac{1}{2}}} + i \frac{- 1 + 3}{2 ^{\frac{1}{2}}}

簡素化

38 (cos (\frac{\frac{π}{4} + 2 \cdot 1 π}{3}) + i sin (\frac{\frac{π}{4} + 2 \cdot 1 π}{3})) : - 2^{\frac{1}{2}} + 2^{\frac{1}{2}} i

簡素化

38 (cos (\frac{\frac{π}{4} + 2 \cdot 2 π}{3}) + i sin (\frac{\frac{π}{4} + 2 \cdot 2 π}{3})) : \frac{1 - 3 ^{\frac{1}{2}}}{2 ^{\frac{1}{2}}} + i \frac{- 1 - 3}{2 ^{\frac{1}{2}}}

z = \frac{1 + 3 ^{\frac{1}{2}}}{2 ^{\frac{1}{2}}} + i \frac{- 1 + 3}{2 ^{\frac{1}{2}}}, z = - 2^{\frac{1}{2}} + 2^{\frac{1}{2}} i, z = \frac{1 - 3 ^{\frac{1}{2}}}{2 ^{\frac{1}{2}}} + i \frac{- 1 - 3}{2 ^{\frac{1}{2}}}