What are the solutions to the equation s^3=27 ?

The solutions to the equation s^3=27 are s=3,s=-3/2+(3sqrt(3))/2 i,s=-3/2-(3sqrt(3))/2 i

Find the zeros of s^3=27

The zeros of s^3=27 are s=3,s=-3/2+(3sqrt(3))/2 i,s=-3/2-(3sqrt(3))/2 i

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s^{3} = 27

s = 3, s = - \frac{3}{2} + \frac{3 3}{2} i, s = - \frac{3}{2} - \frac{3 3}{2} i

Solution steps

s^{3} = 27

For

x^{3} = f (a)

the solutions are

Simplify

s = 3, s = - \frac{3}{2} + \frac{3 3}{2} i, s = - \frac{3}{2} - \frac{3 3}{2} i

17 c^{1} + 5 c^{2} + 255 c^{3} = 53

x^{4} - x^{3} + 4 x^{2} - 4 x = 0

(2 x + 2) (3 x - 6) (4 x + 12) = 0

(x^{2} + 2) (x^{2} - 12) = 72

- 5 + 4 m^{3} = 103

What are the solutions to the equation s^3=27 ?
The solutions to the equation s^3=27 are s=3,s=-3/2+(3sqrt(3))/2 i,s=-3/2-(3sqrt(3))/2 i
Find the zeros of s^3=27
The zeros of s^3=27 are s=3,s=-3/2+(3sqrt(3))/2 i,s=-3/2-(3sqrt(3))/2 i