解
z5=2−2i
解
z=421074+10+25−i421074−10+25,z=421074−10−25+i421074+10−25,z=−22107+i22107,z=−421074+10−25−i421074−10−25,z=421074−10+25−i421074+10+25
解答ステップ
z5=2−2i
zn=aの場合, 解は zk=n∣a∣(cos(narg(a)+2kπ)+isin(narg(a)+2kπ)),
k=0,1,…,n−1
以下のため: n=5,a=2−2i∣a∣=2
arg(a)=−4π
z=52(cos(5−4π+2⋅0π)+isin(5−4π+2⋅0π)),z=52(cos(5−4π+2⋅1π)+isin(5−4π+2⋅1π)),z=52(cos(5−4π+2⋅2π)+isin(5−4π+2⋅2π)),z=52(cos(5−4π+2⋅3π)+isin(5−4π+2⋅3π)),z=52(cos(5−4π+2⋅4π)+isin(5−4π+2⋅4π))
簡素化 52(cos(5−4π+2⋅0π)+isin(5−4π+2⋅0π)):421074+10+25−i421074−10+25
簡素化 52(cos(5−4π+2⋅1π)+isin(5−4π+2⋅1π)):421074−10−25+i421074+10−25
簡素化 52(cos(5−4π+2⋅2π)+isin(5−4π+2⋅2π)):−22107+i22107
簡素化 52(cos(5−4π+2⋅3π)+isin(5−4π+2⋅3π)):−421074+10−25−i421074−10−25
簡素化 52(cos(5−4π+2⋅4π)+isin(5−4π+2⋅4π)):421074−10+25−i421074+10+25
z=421074+10+25−i421074−10+25,z=421074−10−25+i421074+10−25,z=−22107+i22107,z=−421074+10−25−i421074−10−25,z=421074−10+25−i421074+10+25