What are the solutions to the equation 9x^4-39x^3+55x^2-7x-10=0 ?

The solutions to the equation 9x^4-39x^3+55x^2-7x-10=0 are x=-1/3 ,x= 2/3 ,x=2+i,x=2-i

Find the zeros of 9x^4-39x^3+55x^2-7x-10=0

The zeros of 9x^4-39x^3+55x^2-7x-10=0 are x=-1/3 ,x= 2/3 ,x=2+i,x=2-i

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9 x^{4} - 39 x^{3} + 55 x^{2} - 7 x - 10 = 0

x = - \frac{1}{3}, x = \frac{2}{3}, x = 2 + i, x = 2 - i

Solution steps

9 x^{4} - 39 x^{3} + 55 x^{2} - 7 x - 10 = 0

Factor

9 x^{4} - 39 x^{3} + 55 x^{2} - 7 x - 10 : (3 x + 1) (3 x - 2) (x^{2} - 4 x + 5)

(3 x + 1) (3 x - 2) (x^{2} - 4 x + 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 1 = 0 or 3 x - 2 = 0 or x^{2} - 4 x + 5 = 0

Solve

3 x + 1 = 0 : x = - \frac{1}{3}

Solve

3 x - 2 = 0 : x = \frac{2}{3}

Solve

x^{2} - 4 x + 5 = 0 : x = 2 + i, x = 2 - i

The solutions are

x = - \frac{1}{3}, x = \frac{2}{3}, x = 2 + i, x = 2 - i

10000000 = 2560000000 (x^{8})

3 x^{3} + 9 x - 1 = 0

15 x^{3} + 14 x^{2} - 8 x = 900

x^{3} + 2 x^{2} + 4 = 0

(1 + 0.25)^{1} = (1 + x)^{15}

What are the solutions to the equation 9x^4-39x^3+55x^2-7x-10=0 ?
The solutions to the equation 9x^4-39x^3+55x^2-7x-10=0 are x=-1/3 ,x= 2/3 ,x=2+i,x=2-i
Find the zeros of 9x^4-39x^3+55x^2-7x-10=0
The zeros of 9x^4-39x^3+55x^2-7x-10=0 are x=-1/3 ,x= 2/3 ,x=2+i,x=2-i