u^3=2

Lösung

u^{3} = 2

u = 32, u = - 32 \frac{1}{2} + 32 \frac{3}{2} i, u = - 32 \frac{1}{2} - 32 \frac{3}{2} i

Schritte zur Lösung

u^{3} = 2

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

u = 32, u = 32 \frac{- 1 + 3 i}{2}, u = 32 \frac{- 1 - 3 i}{2}

Vereinfache

32 \frac{- 1 + 3 i}{2} : - 32 \frac{1}{2} + 32 \frac{3}{2} i

Vereinfache

32 \frac{- 1 - 3 i}{2} : - 32 \frac{1}{2} - 32 \frac{3}{2} i

u = 32, u = - 32 \frac{1}{2} + 32 \frac{3}{2} i, u = - 32 \frac{1}{2} - 32 \frac{3}{2} i

x^{3} - 12 x^{2} + 49 x - 58 = 0

8 = b^{3}

20 x^{3} - 90 x = 0

48.46 x^{3} - 12.6 x + 0.005 = 0

so l v e f or x, x^{5} + x^{3} + x = 3