ax+bsqrt(x)+c=0

Lösung

a x + b x + c = 0

x = \frac{- 2 a c + b ^{2} + b - 4 a c + b ^{2}}{2 a ^{2}}, x = \frac{- 2 a c + b ^{2} - b - 4 a c + b ^{2}}{2 a ^{2}}

Schritte zur Lösung

a x + b x + c = 0

Quadratwurzeln entfernen

b^{2} x = a^{2} x^{2} + 2 a c x + c^{2}

Löse

b^{2} x = a^{2} x^{2} + 2 a c x + c^{2} : x = \frac{- 2 a c + b ^{2} + b - 4 a c + b ^{2}}{2 a ^{2}}, x = \frac{- 2 a c + b ^{2} - b - 4 a c + b ^{2}}{2 a ^{2}}

x = \frac{- 2 a c + b ^{2} + b - 4 a c + b ^{2}}{2 a ^{2}}, x = \frac{- 2 a c + b ^{2} - b - 4 a c + b ^{2}}{2 a ^{2}}

4 = 3 x - 2

3 x - x + 6 = 0

so l v e f or x, x + y = x y

x + 3 = 6

x^{\frac{2}{3}} = 3