-16t^2+144t+160=0

解

- 16 t^{2} + 144 t + 160 = 0

t = - 1, t = 10

解答ステップ

- 16 t^{2} + 144 t + 160 = 0

解くとthe二次式

t_{1, 2} = \frac{- 144 \pm 14 4 ^{2} - 4 ( - 16 ) \cdot 160}{2 ( - 16 )}

14 4^{2} - 4 (- 16) \cdot 160 = 176

t_{1, 2} = \frac{- 144 \pm 176}{2 ( - 16 )}

解を分離する

t_{1} = \frac{- 144 + 176}{2 ( - 16 )}, t_{2} = \frac{- 144 - 176}{2 ( - 16 )}

t = \frac{- 144 + 176}{2 ( - 16 )} : - 1

t = \frac{- 144 - 176}{2 ( - 16 )} : 10

二次equationの解:

t = - 1, t = 10