b(x)=-3sqrt(-x)+1

Lösung

b (x) = - 3 - x + 1

x = \frac{2 b - 9 + 3 - 4 b + 9}{2 b ^{2}} {b < 0 or 0 < b \leq \frac{9}{4}}, x = \frac{2 b - 9 - 3 - 4 b + 9}{2 b ^{2}} {0 < b \leq \frac{9}{4}}

Schritte zur Lösung

b (x) = - 3 - x + 1

Quadratwurzeln entfernen

b^{2} x^{2} - 2 b x + 1 = - 9 x

Löse

b^{2} x^{2} - 2 b x + 1 = - 9 x : x = \frac{2 b - 9 + 3 - 4 b + 9}{2 b ^{2}}, x = \frac{2 b - 9 - 3 - 4 b + 9}{2 b ^{2}}

x = \frac{2 b - 9 + 3 - 4 b + 9}{2 b ^{2}}, x = \frac{2 b - 9 - 3 - 4 b + 9}{2 b ^{2}}

Überprüfe die Lösungen:

x = \frac{2 b - 9 + 3 - 4 b + 9}{2 b ^{2}} {b < 0 or 0 < b \leq \frac{9}{4}}, x = \frac{2 b - 9 - 3 - 4 b + 9}{2 b ^{2}} {0 < b \leq \frac{9}{4}}

Die Lösungen sind

x = \frac{2 b - 9 + 3 - 4 b + 9}{2 b ^{2}} {b < 0 or 0 < b \leq \frac{9}{4}}, x = \frac{2 b - 9 - 3 - 4 b + 9}{2 b ^{2}} {0 < b \leq \frac{9}{4}}

6 x - 10 = 4

0 = (x 4 - x^{2})^{2}

3 x = 2 4 x

x^{\frac{2}{3}} = - 16

so l v e f or x, x - 3 + 5 = x