n(x)=-4sqrt(x)+2

解

n (x) = - 4 x + 2

x = \frac{4 n + 16 + 128 n + 256}{2 n ^{2}} {- 2 \leq n < 0}, x = \frac{4 n + 16 - 128 n + 256}{2 n ^{2}} {- 2 \leq n < 0 or n > 0}

解答ステップ

n (x) = - 4 x + 2

平方根を削除する

n^{2} x^{2} - 4 n x + 4 = 16 x

解く

n^{2} x^{2} - 4 n x + 4 = 16 x : x = \frac{4 n + 16 + 128 n + 256}{2 n ^{2}}, x = \frac{4 n + 16 - 128 n + 256}{2 n ^{2}}

x = \frac{4 n + 16 + 128 n + 256}{2 n ^{2}}, x = \frac{4 n + 16 - 128 n + 256}{2 n ^{2}}

解を検算する:

x = \frac{4 n + 16 + 128 n + 256}{2 n ^{2}} {- 2 \leq n < 0}, x = \frac{4 n + 16 - 128 n + 256}{2 n ^{2}} {- 2 \leq n < 0 or n > 0}

解答は

x = \frac{4 n + 16 + 128 n + 256}{2 n ^{2}} {- 2 \leq n < 0}, x = \frac{4 n + 16 - 128 n + 256}{2 n ^{2}} {- 2 \leq n < 0 or n > 0}