What is the answer to solvefor x,sqrt(x)-1=y ?

The answer to solvefor x,sqrt(x)-1=y is x=y^2+2y+1 {y>=-1}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,sqrt(x)-1=y

solve for

x, x - 1 = y

x = y^{2} + 2 y + 1 {y \geq - 1}

Solution steps

x - 1 = y

Move

1

to the right side

x = y + 1

Square both sides:

x = y^{2} + 2 y + 1

x = y^{2} + 2 y + 1

Verify Solutions:

x = y^{2} + 2 y + 1 {y \geq - 1}

The solution is

x = y^{2} + 2 y + 1 {y \geq - 1}

16 + 6 + x = 12

4 = \frac{g}{0.5}

x = - x^{2}

x^{3} = 2 x - 5

- 4 + 2 - x = x

What is the answer to solvefor x,sqrt(x)-1=y ?
The answer to solvefor x,sqrt(x)-1=y is x=y^2+2y+1 {y>=-1}