What is the answer to 2x+2-3(x+1)^{2/3}=0 ?

The answer to 2x+2-3(x+1)^{2/3}=0 is x=-1,x= 19/8

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2x+2-3(x+1)^{2/3}=0

2 x + 2 - 3 (x + 1)^{\frac{2}{3}} = 0

x = - 1, x = \frac{19}{8}

Decimal Notation

x = - 1, x = 2.375

Solution steps

2 x + 2 - 3 (x + 1)^{\frac{2}{3}} = 0

Remove roots

- 27 x^{2} - 54 x - 27 = - 8 x^{3} - 24 x^{2} - 24 x - 8

Solve

- 27 x^{2} - 54 x - 27 = - 8 x^{3} - 24 x^{2} - 24 x - 8 : x = - 1, x = \frac{19}{8}

x = - 1, x = \frac{19}{8}

Verify Solutions:

x = - 1

True

, x = \frac{19}{8}

True

The solutions are

x = - 1, x = \frac{19}{8}

y, x = 10 y^{\frac{1}{3}}

4 x + 8 = 24

9 x + 1 = 5 x + 11

1.7565 = 2 π \frac{0.81}{g}

w = 7 w - 12

What is the answer to 2x+2-3(x+1)^{2/3}=0 ?
The answer to 2x+2-3(x+1)^{2/3}=0 is x=-1,x= 19/8
Solve for x: 2x+2-3(x+1)^{2/3}=0
The solution is x=-1,x= 19/8