What is the answer to sqrt(9x^2-5)-3x+1=0 ?

The answer to sqrt(9x^2-5)-3x+1=0 is x=1

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sqrt(9x^2-5)-3x+1=0

9 x^{2} - 5 - 3 x + 1 = 0

x = 1

Solution steps

9 x^{2} - 5 - 3 x + 1 = 0

Remove square roots

9 x^{2} - 5 = 9 x^{2} - 6 x + 1

Solve

9 x^{2} - 5 = 9 x^{2} - 6 x + 1 : x = 1

x = 1

Verify Solutions:

x = 1

True

The solution is

x = 1

x - x = 2

7 + 2 + x - 3 = 3

x + 11 = \frac{x ^{2} + 1}{2}

x - 5 - 4 x - 7 = 0

(x + 1)^{\frac{1}{3}} = 0

What is the answer to sqrt(9x^2-5)-3x+1=0 ?
The answer to sqrt(9x^2-5)-3x+1=0 is x=1
Solve for x: sqrt(9x^2-5)-3x+1=0
The solution is x=1