What is the answer to sqrt(y^2-2y+1+y)=5 ?

The answer to sqrt(y^2-2y+1+y)=5 is y=(1+sqrt(97))/2 ,y=(1-sqrt(97))/2

Solve for y: sqrt(y^2-2y+1+y)=5

The solution is y=(1+sqrt(97))/2 ,y=(1-sqrt(97))/2

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y^{2} - 2 y + 1 + y = 5

y = \frac{1 + 97}{2}, y = \frac{1 - 97}{2}

Decimal Notation

y = 5.42442 \dots, y = - 4.42442 \dots

Solution steps

y^{2} - 2 y + 1 + y = 5

Square both sides:

y^{2} - y + 1 = 25

y^{2} - y + 1 = 25

Solve

y^{2} - y + 1 = 25 : y = \frac{1 + 97}{2}, y = \frac{1 - 97}{2}

y = \frac{1 + 97}{2}, y = \frac{1 - 97}{2}

Verify Solutions:

y = \frac{1 + 97}{2}

True

, y = \frac{1 - 97}{2}

True

The solutions are

y = \frac{1 + 97}{2}, y = \frac{1 - 97}{2}

4096 x = 64 x^{2}

21 - x = x - 1

x - 1 + x = 2

6 = 121 - x

(\frac{1 - x}{x}) = 2.59

What is the answer to sqrt(y^2-2y+1+y)=5 ?
The answer to sqrt(y^2-2y+1+y)=5 is y=(1+sqrt(97))/2 ,y=(1-sqrt(97))/2
Solve for y: sqrt(y^2-2y+1+y)=5
The solution is y=(1+sqrt(97))/2 ,y=(1-sqrt(97))/2