What is the answer to solvefor y,x=sqrt(y)-2 ?

The answer to solvefor y,x=sqrt(y)-2 is y=x^2+4x+4 {x>=-2}

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solvefor y,x=sqrt(y)-2

solve for

y, x = y - 2

y = x^{2} + 4 x + 4 {x \geq - 2}

Solution steps

x = y - 2

Switch sides

y - 2 = x

Move

2

to the right side

y = x + 2

Square both sides:

y = x^{2} + 4 x + 4

y = x^{2} + 4 x + 4

Verify Solutions:

y = x^{2} + 4 x + 4 {x \geq - 2}

The solution is

y = x^{2} + 4 x + 4 {x \geq - 2}

y, x = y - 4

y, x = y + 2

(x + 6)^{3} = 125

6 x = 30

6 x = 2 x

What is the answer to solvefor y,x=sqrt(y)-2 ?
The answer to solvefor y,x=sqrt(y)-2 is y=x^2+4x+4 {x>=-2}