1-2asqrt(1-a^2)=2a^2

Lösung

1 - 2 a 1 - a^{2} = 2 a^{2}

a = - \frac{2 + 1}{4 2 ^{3}}, a = \frac{2 - 1}{4 2 ^{3}}

Dezimale

a = - 0.92387 \dots, a = 0.38268 \dots

Schritte zur Lösung

1 - 2 a 1 - a^{2} = 2 a^{2}

Quadratwurzeln entfernen

4 a^{2} - 4 a^{4} = 4 a^{4} - 4 a^{2} + 1

Löse

4 a^{2} - 4 a^{4} = 4 a^{4} - 4 a^{2} + 1 : a = \frac{2 + 1}{4 2 ^{3}}, a = - \frac{2 + 1}{4 2 ^{3}}, a = \frac{2 - 1}{4 2 ^{3}}, a = - \frac{2 - 1}{4 2 ^{3}}

a = \frac{2 + 1}{4 2 ^{3}}, a = - \frac{2 + 1}{4 2 ^{3}}, a = \frac{2 - 1}{4 2 ^{3}}, a = - \frac{2 - 1}{4 2 ^{3}}

Überprüfe die Lösungen:

a = \frac{2 + 1}{4 2 ^{3}}

Falsch

, a = - \frac{2 + 1}{4 2 ^{3}}

Wahr

, a = \frac{2 - 1}{4 2 ^{3}}

Wahr

, a = - \frac{2 - 1}{4 2 ^{3}}

Falsch

Die Lösungen sind

a = - \frac{2 + 1}{4 2 ^{3}}, a = \frac{2 - 1}{4 2 ^{3}}

- 3 x + 1 + 3 x + 4 = 3

x + 2 - 2 x + 5 = 5

4 x^{2} - 1 = 0

G (x) = x^{2} - 16

3 x^{2} + 1 + 4 = 0