What are the solutions to the equation 1^2+x^2=6^2 ?

The solutions to the equation 1^2+x^2=6^2 are x=sqrt(35),x=-sqrt(35)

Find the zeros of 1^2+x^2=6^2

The zeros of 1^2+x^2=6^2 are x=sqrt(35),x=-sqrt(35)

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1^{2} + x^{2} = 6^{2}

x = 35, x = - 35

Decimal Notation

x = 5.91607 \dots, x = - 5.91607 \dots

Solution steps

1^{2} + x^{2} = 6^{2}

Move

1^{2}

to the right side

x^{2} = 35

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 35, x = - 35

ln (\frac{1}{x ^{2}})

5 x - 15 = - 60

x^{2} - 18 x - 40

5 x - 4 = 3 x - 2

- 32 > 1.6 h

What are the solutions to the equation 1^2+x^2=6^2 ?
The solutions to the equation 1^2+x^2=6^2 are x=sqrt(35),x=-sqrt(35)
Find the zeros of 1^2+x^2=6^2
The zeros of 1^2+x^2=6^2 are x=sqrt(35),x=-sqrt(35)