What is the answer to solvefor y,x=4y^{-0.4} ?

The answer to solvefor y,x=4y^{-0.4} is y=(32)/(x^2sqrt(x)),y=-(32)/(x^2sqrt(x))

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solvefor y,x=4y^{-0.4}

solve for

y, x = 4 y^{- 0.4}

y = \frac{32}{x ^{2} x}, y = - \frac{32}{x ^{2} x}

Solution steps

x = 4 y^{- 0.4}

Expand

4 y^{- 0.4} : \frac{4}{y ^{0.4}}

x = \frac{4}{y ^{0.4}}

Take both sides of the equation to the power of

5 : x^{5} = \frac{1024}{y ^{2}}

x^{5} = \frac{1024}{y ^{2}}

Solve

x^{5} = \frac{1024}{y ^{2}} : y = \frac{32}{x ^{2} x}, y = - \frac{32}{x ^{2} x}

y = \frac{32}{x ^{2} x}, y = - \frac{32}{x ^{2} x}

Verify Solutions:

y = \frac{32}{x ^{2} x}

True

, y = - \frac{32}{x ^{2} x}

True

The solutions are

y = \frac{32}{x ^{2} x}, y = - \frac{32}{x ^{2} x}

4.8 = \frac{k}{0.32}

x^{2} + x + 1 = 0

x, 31 - 6 x - x + 6 = 0

t - 3 = 11

m = 9

What is the answer to solvefor y,x=4y^{-0.4} ?
The answer to solvefor y,x=4y^{-0.4} is y=(32)/(x^2sqrt(x)),y=-(32)/(x^2sqrt(x))