3+sqrt(-x^2+4)=x^211

Lösung

3 + - x^{2} + 4 = x^{2} 11

x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}

Dezimale

x = 0.66644 \dots, x = - 0.66644 \dots

Schritte zur Lösung

3 + - x^{2} + 4 = x^{2} \cdot 11

Quadratwurzeln entfernen

- x^{2} + 4 = 121 x^{4} - 66 x^{2} + 9

Löse

- x^{2} + 4 = 121 x^{4} - 66 x^{2} + 9 : x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}, x = \frac{65 - 19 5}{11 2}, x = - \frac{65 - 19 5}{11 2}

x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}, x = \frac{65 - 19 5}{11 2}, x = - \frac{65 - 19 5}{11 2}

Überprüfe die Lösungen:

x = \frac{65 + 19 5}{11 2}

Wahr

, x = - \frac{65 + 19 5}{11 2}

Wahr

, x = \frac{65 - 19 5}{11 2}

Falsch

, x = - \frac{65 - 19 5}{11 2}

Falsch

Die Lösungen sind

x = \frac{65 + 19 5}{11 2}, x = - \frac{65 + 19 5}{11 2}

(2 x - 7)^{\frac{3}{4}} + 6 = 14

x + 5 - 2 = 5 - 2

3 + - x^{2} + 4 = x^{2} - 1

3 7 v - 8 = 3

0 = 2.5 4 x - x - 1