What is the answer to solvefor x,(sqrt(x^2-1))y=1 ?

The answer to solvefor x,(sqrt(x^2-1))y=1 is x=(sqrt(y^2+1))/y ,x=-(sqrt(y^2+1))/y

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solvefor x,(sqrt(x^2-1))y=1

solve for

x, (x^{2} - 1) y = 1

x = \frac{y ^{2} + 1}{y}, x = - \frac{y ^{2} + 1}{y}

Solution steps

(x^{2} - 1) y = 1

Divide both sides by

y

x^{2} - 1 = \frac{1}{y}

Square both sides:

x^{2} - 1 = \frac{1}{y ^{2}}

x^{2} - 1 = \frac{1}{y ^{2}}

Solve

x^{2} - 1 = \frac{1}{y ^{2}} : x = \frac{y ^{2} + 1}{y}, x = - \frac{y ^{2} + 1}{y}

x = \frac{y ^{2} + 1}{y}, x = - \frac{y ^{2} + 1}{y}

Verify Solutions:

x = \frac{y ^{2} + 1}{y}

True

, x = - \frac{y ^{2} + 1}{y}

True

The solutions are

x = \frac{y ^{2} + 1}{y}, x = - \frac{y ^{2} + 1}{y}

1 + x + 1 = 4

u + 3 = 8

x - 17 x + 70 = 0

y, x = y^{2} + 7 - 1

13 7^{2} + 2 3^{2} = x

What is the answer to solvefor x,(sqrt(x^2-1))y=1 ?
The answer to solvefor x,(sqrt(x^2-1))y=1 is x=(sqrt(y^2+1))/y ,x=-(sqrt(y^2+1))/y