q^2+2q-35=0

解

q^{2} + 2 q - 35 = 0

q = 5, q = - 7

解答ステップ

q^{2} + 2 q - 35 = 0

解くとthe二次式

q_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 35 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 35) = 12

q_{1, 2} = \frac{- 2 \pm 12}{2 \cdot 1}

解を分離する

q_{1} = \frac{- 2 + 12}{2 \cdot 1}, q_{2} = \frac{- 2 - 12}{2 \cdot 1}

q = \frac{- 2 + 12}{2 \cdot 1} : 5

q = \frac{- 2 - 12}{2 \cdot 1} : - 7

二次equationの解:

q = 5, q = - 7