|6x^2+x-11|=4

Lösung

6 x^{2} + x - 11 = 4

x = - \frac{5}{3} or x = - \frac{7}{6} or x = 1 or x = \frac{3}{2}

Dezimale

x = - 1.66666 \dots, x = - 1.16666 \dots, x = 1, x = 1.5

Schritte zur Lösung

6 x^{2} + x - 11 = 4

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

6 x^{2} + x - 11 = - 4 or 6 x^{2} + x - 11 = 4

6 x^{2} + x - 11 = - 4 or 6 x^{2} + x - 11 = 4

(x = - \frac{7}{6} or x = 1) or (x = - \frac{5}{3} or x = \frac{3}{2})

x = - \frac{5}{3} or x = - \frac{7}{6} or x = 1 or x = \frac{3}{2}

4 ∣ v - 5 ∣ = 16

\frac{1}{3} x + 4 = 3

∣ f - 6 ∣ = f + 8

∣ 3 x - 4 ∣ = 1

∣ x - 4 ∣ = - 2