|x^2+2x-9|=6

Lösung

x^{2} + 2 x - 9 = 6

x = - 5 or x = - 3 or x = 1 or x = 3

Schritte zur Lösung

x^{2} + 2 x - 9 = 6

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 2 x - 9 = - 6 or x^{2} + 2 x - 9 = 6

x^{2} + 2 x - 9 = - 6 or x^{2} + 2 x - 9 = 6

(x = - 3 or x = 1) or (x = - 5 or x = 3)

x = - 5 or x = - 3 or x = 1 or x = 3

∣ x + 3 ∣ = 2 x

6 ∣ 1 - 5 x ∣ = 54

∣ 6 + 4 x ∣ = 30

∣ 3 v - 9 ∣ = 3

∣ x - 2 ∣ = x - 2