|x^2-4x+5|=2

Lösung

x^{2} - 4 x + 5 = 2

x = 1 or x = 3

Schritte zur Lösung

x^{2} - 4 x + 5 = 2

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} - 4 x + 5 = - 2 or x^{2} - 4 x + 5 = 2

x^{2} - 4 x + 5 = - 2 or x^{2} - 4 x + 5 = 2

keine L \overset{o}{¨} sung or (x = 1 or x = 3)

x = 1 or x = 3

\frac{1}{5} ∣ 3 x + 8 ∣ = 7

∣ - 6 q - 200 ∣ = 160

∣ 5 x + 10 ∣ = 0

3 ∣ 2 x + 3 ∣ + 4 = 14

∣ 3 x + 9 ∣ = 0