|x^2+3x|=4

Lösung

x^{2} + 3 x = 4

x = - 4 or x = 1

Schritte zur Lösung

x^{2} + 3 x = 4

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 3 x = - 4 or x^{2} + 3 x = 4

x^{2} + 3 x = - 4 or x^{2} + 3 x = 4

keine L \overset{o}{¨} sung or (x = - 4 or x = 1)

x = - 4 or x = 1

∣ 7 x ∣ + 8 = 15

- ∣ 7 - x ∣ - 5 = - 12 - 12

- 5 = \frac{∣ r - 7 ∣}{- 3}

4 = ∣ v + 6 ∣

∣ 3 - 2 t ∣ + 4 = 15