2|2[3(x+1)-3]|+1=13

解

2 ∣ 2 [3 (x + 1) - 3] ∣ + 1 = 13

x = - 1 or x = 1

解答ステップ

2 ∣ 2 [3 (x + 1) - 3] ∣ + 1 = 13

1

を右側に移動します

2 ∣ 2 [3 (x + 1) - 3] ∣ = 12

以下で両辺を割る

2

∣ 2 [3 (x + 1) - 3] ∣ = 6

絶対規則を適用する:

∣ u ∣ = a, a > 0

の場合は

u = a

u = - a

2 [3 (x + 1) - 3] = - 6 or 2 [3 (x + 1) - 3] = 6

2 [3 (x + 1) - 3] = - 6 or 2 [3 (x + 1) - 3] = 6

x = - 1 or x = 1