|x^2+1|=10

Lösung

x^{2} + 1 = 10

x = - 3 or x = 3

Schritte zur Lösung

x^{2} + 1 = 10

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

x^{2} + 1 = - 10 or x^{2} + 1 = 10

x^{2} + 1 = - 10 or x^{2} + 1 = 10

keine L \overset{o}{¨} sung or (x = - 3 or x = 3)

x = - 3 or x = 3

- ∣ r ∣ = 18

\frac{8 x - 4}{3} = 6

∣ 2 x - 5 ∣ = 2

∣ 8 b ∣ - 1 = 16

5 ∣ 6 n - 2 ∣ + 4 = - 36